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Moteur de recherche de fiches techniques de composants électroniques |
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Moteur de recherche de fiches techniques de composants électroniques |
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CXA3741AUR Fiches technique(PDF) 8 Page - Sony Corporation |
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CXA3741AUR Fiches technique(HTML) 8 Page - Sony Corporation |
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8 / 15 page  CXA3741AUR - 8 - Description of Operation Current Settings 1. Output Drive Current The small signal output impedance of the OUT pin (Pin 14) can be set by connecting the IDRV0 pin (Pin 2) or the IDRV1 pin (Pin 3) to VCC through a resistor. The inflow current to the IDRV pin is multiplied by 10 times inside the IC, and flows as the output stage idling current. The IDRV pins have internal 50k Ω resistors. When the drive current setting switching pin DRVCNT (Pin 16) input logic is low, the inflow current to the IDRV pin is set according to the current set by the IDRV0 pin (Pin 2). When high, the inflow current to the IDRV pin is set according to the current set by the IDRV1 pin (Pin 3). The above-mentioned inflow current to the IDRV pin can be calculated as follows. IIDRV = (VCC – VBE × 2)/(RIDRV + 50kΩ) = (15 – 1.46)/270k Ω = 50.1 μA Here, VCC = 15V, VBE = 0.73V (typ.), and RIDRV = 220k Ω. The small signal output impedance at this time can be calculated as follows. ROUT = (26mV/(10 × IIDRV))/2 = (26mV/501 μA)/2 = 26 Ω 2. Sink Current for CCD with Open Source Output The sink current of the IN pin (Pin 10) can be set by connecting the ISF0 pin (Pin 6) or the ISF1 pin (Pin 7) to VCC through a resistor. This sink current can be used as the CCD output stage source follower drive current. The inflow current to the ISF pin is multiplied by 58 times inside the IC, and flows as the sink current. The ISF pins have internal 50k Ω resistors. When the CCD source follower output sink current setting switching pin SFCNT (Pin 1) input logic is low, the inflow current to the ISF pin is set according to the current set by the ISF0 pin (Pin 6). When high, the inflow current to the ISF pin is set according to the current set by the ISF1 pin (Pin 7). The above-mentioned inflow current to the ISF pin can be calculated as follows. IISF = (VCC – VBE × 2)/(RISF + 50kΩ) = (15 – 1.46)/270k Ω = 50.1 μA Here, VCC = 15V, VBE = 0.73V (typ.), and RISF = 220k Ω. The sink current at this time can be calculated as follows. Isink = 58 × IISF = 2.9mA Note) This IC operation depends on IDRV and ISF. This specification is described based on IDRV of 220k Ω when VCC = 15V. However , set it to 180kΩ to occur the same current when using under the condition that VCC = 13V. [IDRV and ISF vs external resistor] Current ( μA) 90 68 50 35 26 Unit When VCC = 15V 100 150 220 330 470 k Ω When VCC = 13V 78 120 180 270 390 k Ω |
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Description similaire - CXA3741AUR |
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